Summary

Physical QuantityFirst-order TransformationSecond-order TransformationKey Note (重点)
$G$ContinuousContinuousEquilibrium requires equal $G$ for both phases.
$S, V, H$DiscontinuousContinuousFirst-order has latent heat/volume change; second-order does not.
1st derivatives of $G$DiscontinuousContinuousTied to $S$ and $V$ continuity.
2nd derivatives of $G$ContinuousDiscontinuousSecond-order has sudden heat capacity change.
InterfaceExists (clear boundary)None (smooth transition)First-order needs “nucleation + growth” to form new phase .
Latent HeatYesNo

The core function is:

$$G=H-TS$$

Where:

  • $G$ = Gibbs free energy
  • $H$ = Enthalpy (related to energy of bonding)
  • $S$ = Entropy (related to atomic order)
  • $T$ = Temperature

First-order的$H,S$不连续,因此具有明显的interface;而Second-order的$H,S$是连续点,不具有鲜明的interface,因此二阶相变不涉及interface energy.

First-order transmission的interface energy(surface energy)是 “nucleation” 的阻力 —— 需要过冷度提供额外能量来克服界面能,才能形成新相的晶核.


Second-order transition


0 条评论

发表回复

Avatar placeholder

您的邮箱地址不会被公开。 必填项已用 * 标注